Webinar Critical Path : Q5

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namita
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Webinar Critical Path : Q5

Postby namita Wed Jan 01, 2014 10:52 am

Calculate the following for this N/W Diagram :
Float of each activity
Critical Path
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Pashi
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Re: Webinar Critical Path : Q5

Postby Pashi Fri Jan 03, 2014 3:33 am

Please see attached the solution.
i) - Critical Path - ACDF

4 possible Paths -
ACDF = 27
ABDF = 22
ACDE = 24
ABDE = 19

Since ACDF = 27, is the longest path, hence the CRITICAL PATH.

ii) Float on each Activity-
Critical path = ACDF and float on all activities on Critical path = 0, so -
Float on A = 0, Float on C = 0, Float on D = 0, Float on F = 0.

Now, Subtract the Second Longest path in the N/W Diagram from the Critical Path, this will give the float on each activity on second longest path.
i.e. ACDF - ACDE => 27-24 = 3 (Float on all activities on the second longest path EXCLUDING the CRITICAL PATH activities on this path (if any)).
Since A, C and D are on CP so float on them is 0. Remaining activity is E, hence float on E=3. :mrgreen:

Repeating above on Third Longest Path in the N/W Diagram from the Critical Path.

ACDF - ABDF = 27-22 = 5.

Since A, C and D are on CP so float on them is 0, Remaining Activity is B, hence Float on B=5.. :mrgreen:

Alternate Solution is to find out the Es, Ef, Ls, Lf on all activities and calculate the float. But if the question is limited to identify Float only, I would stick to this method as it saves me some time. 8-)
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namita
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Re: Webinar Critical Path : Q5

Postby namita Fri Jan 03, 2014 4:34 am

Right approach... same will be discussed in webinar. Also if n/w diagram is not very complex...forward path and backward path method is recommended

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